Вопрос школьника по предмету Алгебра
Помогите решить систему неравенств:
x^2-5x-14>0
x^2-2x-35<0
Ответ учителя по предмету Алгебра
1) х²-5х-14 > 0
D = 25+56 = 81
x₁= 5-9 / 2 = -2
x₂= 5+9 / 2 = 7
+ — +
———₀———₀——->x
\ -2 7 /////////
2) х²-2х-35 < 0
D = 4+140 = 144
x₁ = 2-12 / 2 = -5
x₂ = 2+12 / 2 = 7
+ — +
———-₀———₀———>x
-5 //////// 7
\\\ -2 7 /////////
——₀———₀—————-₀——->x
-5 \\\\\ 7
x∈(-5; -2)
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