Вопрос школьника по предмету Математика
Помогите, нужно найти приближение числа а) 2,36 разряд округления 0,1 с избытком и с недостатком б) 16,783 разряд округления 0,01 с избытком и с недостатком в) 3,8147 разряд округления 0,001 с избытком и с недостатком
Ответ учителя по предмету Математика
2.36=2.3
16.783=1.67
3.8147=1.814
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