Вопрос школьника по предмету Химия
рассчитайте массовую долю воды в составе: б) дигидрате хлорида бария BaCl2 * 2H20 в)глауберовой соли Na2SO4 * 10H2 O г)тригидрата нитрита меди(2) Cu(N03)2*3H2()
Ответ учителя по предмету Химия
ω(H₂O) = m(H₂O) ÷ m(
BaCl₂
* 2H₂O) *100% = 36÷ 244 = 14, 75%
ω(H₂O) = 180 ÷ 322 * 100% = 55, 9%
ω(H₂O) = 54 ÷242 * 100% = 22,31%
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