Вопрос школьника по предмету Химия
При взаимодействии оксида цинка с азотной кислотой образуется нитрат цинка и вода:
ZnO + 2HNO3 → Zn(NO3)2+ H2O
Вычисли, какая масса азотной кислоты расходуется на реакцию с 1,62 г оксида цинка.
(Ответ впиши с точностью 2 знака после запятой)
Ответ: m(HNO3)=_г
Ответ учителя по предмету Химия
дано
m(ZnO)=1.62 g
———————-
m(HNO3)-?
1.62 X
ZnO+2HNO3—>Zn(NO3)2+H2O M(ZnO)=81 g/mol , M(HNO3)=63 g/mol
81 2*63
1.62/81 = X/126
X=2.52 g
ответ m(HNO3)=2.52 g
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