Ответ учителя по предмету Химия
дано
m(CaCO3)=53 g
W(пр)=10%
H2SO4
——————-
V(CO2)-?
m(чист CaCO3)=53-(53*10%/100%)=47.7 g
47.7 X
CaCO3+H2SO4—>CaSO4+CO2+H2O
100 22.4
M(CaCO3)=100 g/mol , Vm=22.4L/mol
47.7 / 100 = X / 22.4
x=10.68 L
ответ 10.68 л
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