Вопрос школьника по предмету Алгебра
547. Разложите на множители:
1) sin2g. – 2sina; 2) sina +sin a2
3) cosa — sin2а; 4) 1- sin2а – cos®а.срочно помогите пожалуйста
пожалуйста помогите
Ответ учителя по предмету Алгебра
Ответ:
Объяснение:
1) =2sina*cosa-2sina=2sina(cosa-1)
2) =2sin a/2*cos a/2+sin a/2=sin a/2(2cos a/2+1)
3) =cos a-2sina*cosa=cosa(1-2sina)
4) =(1-cos^2a)-sin2a=sin^2 a -2sina*cosa=sina(sina-2cosa)
формулы: sin2a=2sina*cosa
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