Ответ учителя по предмету Химия
1. n(Fe) = N/Na = 1.5 * 10^23 : 6 * 10^23 моль^-1 = 0.25 моль
2. n(O2) = N/Na = 3.01 * 10^23 : 6.02 * 10^23 моль^-1 = 0.5 моль
1. n(Fe) = N/Na = 1.5 * 10^23 : 6 * 10^23 моль^-1 = 0.25 моль
2. n(O2) = N/Na = 3.01 * 10^23 : 6.02 * 10^23 моль^-1 = 0.5 моль
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