Вопрос школьника по предмету Алгебра
упростите выражение 2sin^2a*ctga/sin2a
пожалуйста срочно нужно!
Ответ учителя по предмету Алгебра
2sin²a•ctga/sin2a = 2sin²a•(cosa/sina)/sin2a = 2sinacosa/sin2a = 2sinacosa/2sinacosa = 1.
Мы пользовались формулами:
ctga = cosa/sina и sin2a = 2sinacosa.
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21+x=6
4-5x=0
0.5x+20.1=0.1
x+3/2=-7 там в числители x+3 а в знаминателе 2
9-x/7=-1 сдесь точно также
Помогите пожалуйста!
Заранее спасибо большое!
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