Вопрос школьника по предмету Математика
Тендеудi шешiндер:
1) 5(3-2у)-4(9-у)=3(у+5);
2) 14(2х-3)-5(х+4)=2(3х+5)+5х
3)9(3х-7)+3(8х-11)=3(9х+8)
4)6(7х-11)-13(х-6)=14(2х+1)
Ответ учителя по предмету Математика
……………… …………..
Тендеудi шешiндер:
1) 5(3-2у)-4(9-у)=3(у+5);
2) 14(2х-3)-5(х+4)=2(3х+5)+5х
3)9(3х-7)+3(8х-11)=3(9х+8)
4)6(7х-11)-13(х-6)=14(2х+1)
……………… …………..
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а) 0,35 * х = 56
b) 56 * х = 0,35
c) 0,35 * 56 = х
d) x ÷ 0,35 = 56
С, да?)
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