Вопрос школьника по предмету Алгебра
решить уравнение с факториалами
(x+6)!/(x+3)!=x^3+15x^2+268
Ответ учителя по предмету Алгебра
Так как (x+6)!=(x+3)!*(x+4)*(x+5)*(x+6), то уравнение приводится к виду
(x+4)*(x+5)*(x+6)=x³+15*x²+268, или 74*x-148=0. Отсюда 74*x=148 и x=148/74=2. Ответ: x=2.
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