Вопрос школьника по предмету Алгебра
Решите пожалуйста
tg (x+П/6)=1/корень из 3
Ответ учителя по предмету Алгебра
1) cos x/3 = 1/2
x/3 = ± π/3 + 2πn, n€Z
x = ± π + 6nπ, n€Z
2) tg (x — π6) = 1/корень из 3
(x — π/6) = π/6 + πn, n€Z
x = π/3 +πn, n€Z
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