Вопрос школьника по предмету Химия
Найти массу серной кислоты , необходимой для нейтрализации 200г 20%-ного раствора гидроксида натрия.
Ответ учителя по предмету Химия
дано
m(ppa NaOH)=200 g
W(ppa)=205
———————-
m(H2SO4)=?
m(NaOH)=200*20%/100%=40 g
40 X
2NaOH+H2SO4—>Na2SO4+2H2O M(NaOH)=40 g/mol M(H2SO4)=98 g/mol
2*40 98
X=40*98 / 80=49 g
ответ 49 г
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