Ответ учителя по предмету Алгебра
f(x) = 2x^(-2) — 5x^(-1) + 2
Замена: 1/х = t
2t² — 5t + 2 = 0
D = 25 — 16 = 9
√D = 3
y1 = (5 — 3)/4 = 1/2
y2 = (5 + 3)/4 = 2
возвращаемся к подстановке
1/х = 1/2 → х = 2
1/х = 2 → х = 1/2
Ответ: х1 = 2; х2 = 1/2
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