Вопрос школьника по предмету Физика
Какова длина алюминьевой проволки площадью поперечного сечения 0,04мм^2 при сопротивлении 88 Ом?
Ответ учителя по предмету Физика
R=p*L/S
L=R*S/p=88*0,04/0,028=125,7 м
Какова длина алюминьевой проволки площадью поперечного сечения 0,04мм^2 при сопротивлении 88 Ом?
R=p*L/S
L=R*S/p=88*0,04/0,028=125,7 м
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сладкий-………
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хороший-………….
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Я вас очень прошу ПОМОГИТЕ!!!