Вопрос школьника по предмету Математика
Знайти сторони прямокутного трикутника,якщо АВ=12см,cos кута А=0,6
Знайти сторони прямокутного трикутника,якщо АВ=12см,cos кута А=0,6
Ответ учителя по предмету Математика
Ответ:
16см
Пошаговое объяснение:
AB и BC-катеты
АС-гипотенуза
cosA=AB/AC=0.6
12/AC=0.6
AC=12/0.6
AC=20см
BC=√(AC²-AB²)=√(20²-12²)=√(400-144)=√256=16см
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