Вопрос школьника по предмету Математика
Даны вершины A(1;-3;0) B(-2;-4;1) C(-3;1;1) D(0;2;0) параллелограмма ABCD. Вычислите длины диагоналей параллелограмма
Ответ учителя по предмету Математика
АС=sqrt[(1+3)^2+(1+3)^2+(0+1)^2]=sqrt[16+16+1]=sqrt(33)
BD=sqrt[2^2+6^2+1^2]=sqrt[4+36+1]=sqrt[41]
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