Ответ учителя по предмету Химия
Дано:
V(CO2) = 11,2 л n(CO2) = V(CO2) / Vm= 11,2 / 22,4 =0,5 моль
Vm=22,4 л/моль m(CO2) = n(CO2) * M(CO2) = 0,5 * 44 = 22 г
М(СО2) = 44 г/моль N = Na * n = 6,02 *10²³ * 0,5 = 3,01 *10²³
Na = 6,02 * 10²³ 1/моль
Найти:
n(CO2)
m(CO2)
N
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