Вопрос школьника по предмету Математика
Высота BH параллелограмма ABCD делит его сторону AD на отрезки AH=2 и HD=64. Диагональ параллелограмма BD равна 80. Найдите площадь параллелограмма.
Ответ учителя по предмету Математика
по т. Пифагора:
BH² = BD² — HD²
BH² = 6400 — 4096 = 2304 = 48²
BH = 48
AD = AH + HD = 2 + 64 = 66
S = AD*BH = 66*48 = 3168
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