Вопрос школьника по предмету Математика
Помогите решить такие уравнения :
15*(a+2)=6*(2a+7)=?
12b-7*(b+4)=26-4b=?
5*(3c+2)=8*(9-2c)=?
10R+2*(7R-2)=5*(4R+3)+3R=?
Ответ учителя по предмету Математика
15*(a+2)=6*(2a+7)
15а+30=12а+42
15а-12а=42-30
3а=12
а=12:3
а=4
12b-7*(b+4)=26-4b
12b-7b-28=26-4b
5b+4b=26+28
9b=54
b=54:9
b=6
5*(3c+2)=8*(9-2c)
15c+10=72-16c
15c+16c=72-10
31c=62
c=62:31
c=2
10R+2*(7R-2)=5*(4R+3)+3R
10R+14R-4=20R+15+3R
24R-23R=15+4
R=19
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