Вопрос школьника по предмету Химия
вычислите массу водорода, равную 4,48 л при нормальных условиях
Ответ учителя по предмету Химия
V=4.48 (л)
n=V/Vm, где Vm — объем газа при н.у. =22.4(л/моль)
n=4.48/22.4=0.2(моль)
m=n*M
M(H2)=2*1=2(г/моль)
m=0.2*2=0.4 (г)
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