Вопрос школьника по предмету Математика
sin^2x + корень из 3 sinx*cosx=0
Ответ учителя по предмету Математика
sin^2x+корень из 3sinxcosx=0| делим на cos^2x
tg^2x+корень из 3tgx=0
tgx(tgx+корень из 3)=0
tgx=0 tgx=-корень из 3
tgx=0 x= pi*n , n= z
tgx=-корень из 3 x=
— pi/3 +pi*n, n= z
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