Вопрос школьника по предмету Химия
СРОЧНО!!!
Вычислите массу соляной кислоты, которая потребуется для реакции с порцией оксида меди (||) массой 32 г.
Ответ учителя по предмету Химия
CuO +2HNO3=Cu(NO3)2 +H2O
n(CuO)= m/M= 20/200=0.1 моль
2n(CuO)=n(HNO3)
n(HNO3)=0.2 моль
m(HNO3)= n x M=0.2 x 63=12.6г
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