Вопрос школьника по предмету Химия
какая масса гексана образуется при крекинге 25,2г нонана?
Ответ учителя по предмету Химия
25,2 г Х г
C9H20 -> C3H6 + C6H14
n=1 моль n=1 моль
М = 128 г/моль М = 86 г/моль
m=128 г m=86 г
25,2 г С9Н20 — Х г С6Н14
128 г С9Н20 — 86 г С6Н14
m(C6H14) = 25,2 * 86 / 128 = 16,93 г
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