Вопрос школьника по предмету Физика
Определите КПД наклонной плоскости высотой 3м и длиной 12м, если для подъема тела массой 1000 по этой плоскости прикладывают силу 15000Н
Ответ учителя по предмету Физика
h=3 м L=12 м m=1000 кг F=15000 H η=?
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η=Ап/Аз
Ап=m*g*h
Аз=F*L
η=m*g*h/(F*L)=1000*10*3/(15000*12)=0.17 (17%)
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