Вопрос школьника по предмету Физика
Тело объёмом 1,05м3 погружено керосин.Опредилите выталкивающую силу,действующую на это тело!!! ПОЖАЛУЙСТА
Ответ учителя по предмету Физика
Fa=pgv
p-плотность
g-ускорение свободного падения
v-объем
v=1,05m³
g=9,8
p=0.800 · 103 кг/м³
Fa=0,800*10³(кг/м³) * 9,8(м/с) * 1,05(м³)= 800*10,29=8232 н
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