Вопрос школьника по предмету Алгебра
корень 3x-1- корень 2x-1=7
Ответ учителя по предмету Алгебра
Ответ:
1)
(_/3x-1)(_/2x-1)=7 |^2
(3x-1)(2x-1)=49
6x^2-3x-2x+1-49=0
6x^2-5x-48=0
D=25+48*4*6=
=1177
x1=(5+_/1177)/12
x2=5-_/1177/12
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