Вопрос школьника по предмету Химия
сколько литров кислорода необходимо чтобы сжечь 67.2 л водорода
Ответ учителя по предмету Химия
2H2+O2=2H2O
n(H2)=V(H2) / Vm=67,2 / 22,4=3 моль;
n(O2)=n(H2) / 2=3 / 2=1,5 моль; (по уравнению реакции);
V(O2)=n(O2) * Vm=1,5 * 22,4=33,6 л.
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