Вопрос школьника по предмету Математика
4,2-(5,2-3,8)=
-7,2+(3,8-2,9)=
9,3-(-2,8+3,1)=
-(1,8-1,4)-1,2=
4,7-(2,7-1,14)=
1,16-(3,8-1,2)=
0,2+(a-0,1)=
(t+4)-7=
-(3-a)+4=
-2-(t-1)=
(x-1)-(y+2)=
-(a-2)+(c+3)=
Ответ учителя по предмету Математика
4,2-(5,2-3,8)=2,8
-7,2+(3,8-2,9)=-6,3
9,3-(-2,8+3,1)=9
-(1,8-1,4)-1,2=-1,6
4,7-(2,7-1,14)=3,14
1,16-(3,8-1,2)=-1,44
0,2+(a-0,1)=0,2+a-0,1=0,1+a
(t+4)-7=t+4-7=t-3 t=3
-(3-a)+4=-3+a+4=1+a
-2-(t-1)=-2-t+1=-t-1
(x-1)-(y+2)=x-1-y-2=x-y-3
-(a-2)+(c+3)=-a+2+c+3=a+c+5
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