Вопрос школьника по предмету Химия
10. Обчисліть де більше молекул — у етані масою 6гчи пропані об’ємом 4,48 л?
Дано:
Ответ учителя по предмету Химия
m(C2H6)= 6 г
n(C2H6)= 6/30 = 0.2 моль
N(C2H6)= n*Na = 0.2 * 6.02 * 10²³ = 1.204 * 10²³ молекул;
V(C3H8)= 4.48 л
n(C3H8)= 4.48/22.4 = 0.2 моль
N(C3H8)= n*Na = 0.2 * 6.02 * 10²³ = 1.204 * 10²³ молекул;
Вiдповiдь: однаково.
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