Вопрос школьника по предмету Математика
1. Решите уравнения
5а+3(2a-5)=-4(a+12)-3
6-2(2-2x)=6(х-2)
5(9t-3(2t-4))+13=4(t+10)
2(5х-2(x+3)) -15=10(0,5+0,7x)-11
55-6(1+3(a-7))-4=16+5(a+1)-2а
78-3(5+4(х-3))+10=65-5(3x-1)
(15.302x+4)-13-23-7(х+1)
І
1. Решите уравнения5а+3(2a-5)=-4(a+12)-36-2(2-2x)=6(х-2)5(9t-3(2t-4))+13=4(t+10)2(5х-2(x+3)) -15=10(0,5+0,7x)-1155-6(1+3(a-7))-4=16+5(a+1)-2а78-3(5+4(х-3))+10=65-5(3x-1)(15.302x+4)-13-23-7(х+1)І
Ответ учителя по предмету Математика
Ответ:
1) a=- 12_5
2)x=7
3)t=-15
4)x=-21
5)a=50_7
6)x=-13a
7)8,302x-39
Пошаговое объяснение:
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