Вопрос школьника по предмету Алгебра
(0,2x-3)^2-36=0 помогите решить
Ответ учителя по предмету Алгебра
(0,2x-3)^2-36=0
a² — b² = (a — b)(a + b)
(0,2x-3)^2-6^2=0
(0.2x — 3 — 6)(0.2x — 3 + 6) = 0
(0.2x — 9)(0.2x + 3) = 0
0.2x = 9
x = 45
0,2x = -3
x = -15
ответ -15 и 45
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