Ответ учителя по предмету Химия
1-В KOH + H2SO4(излишек) =
KHSO4 + H2O
2-Д Cu + H2SO4(конц.) =
CUSO4 + SO2 + H2O
3-А K2CO3 + H2SO4 =
K2SO4 + CO2 + H2O
4-Б KOH + H2SО4=
K2SO4 + H2O
1-В KOH + H2SO4(излишек) =
KHSO4 + H2O
2-Д Cu + H2SO4(конц.) =
CUSO4 + SO2 + H2O
3-А K2CO3 + H2SO4 =
K2SO4 + CO2 + H2O
4-Б KOH + H2SО4=
K2SO4 + H2O
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