Вопрос школьника по предмету Физика
Резисторы сопротивлением 3 и 6 Ом соединены параллельно и подключены к источнику тока, напряжением 12 В. Какова сила тока?
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Ответ учителя по предмету Физика
Rобщ.=R=(R1*R2)/(R1+R2)=(3*6)/(3+6)=18/9=2 Ом.
U=12 B.
I=U/R=12/2=6 А.
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