Вопрос школьника по предмету Химия
Осуществить превращение:
Mn-MnO-Mn S04-Mn(OH)2 –MnCl2
Ответ учителя по предмету Химия
Ответ:
Mn→MnO→MnSO4→Mn(OH)2→MnCl2
2Mn+O2 → 2MnO
MnO+H2SO4 → MnSO4+H2O
MnSO4+2NaOH → Mn(OH)2+Na2SO4
Mn(OH)2+2KCl → MnCl2+2KOH
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Реши уравнения, пользуясь основными свойствами уравнений.
1) x — 3 = 5
a — 7 = 3
z — 12 = 22
2) 25 — y = 11
15 — g = 8
3 — x = -4
3) 8x = 72
4x = 44
5x = 0
4) x + 7 = 12
x + 5 = -10
5 — x = 30
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