Перейти к выбору ответа 12.04.2022найдите наименьшее значение функции y=x^3-x^2-40x на отрезке [3;8] Выбрать другой вопрос Смотреть ответ Перейти к выбору ответа Алгебра Ответ учителя по предмету Алгебра y`=3x²-2x-40=0 D=4+480=484 x1=(2-22)/6=-10/3∉[[3;8] x2=(2+22)/6=4∈[3;8] y(3)=27-9-120=-102 y(4)=64-16-160=-112 наим y(8)=512-64-320=128
Похожие вопросы от пользователей
‘So what did you do next?’ asked Holmes. ‘Nothing,’ answered Openshaw. He put his head in his hands. ‘I don’t know what to do. I’m afraid.’ ‘Nothing?’ cried Holmes. ‘Young man, you must do something fast. You’re in danger!’ ‘Well,’ I’ve talked to the police,’ said Openshaw unhappily. ‘But they laughed at me. They think that there’s nothing to worry about.’ ‘How stupid they are!’ cried Holmes. ‘And why didn’t you come to me immediately? Your enemies have had almost two days to make a plan. Haven’t you found anything which will help us?’ ‘Well, I found this in the locked room,’ said John Openshaw. He showed us a small, half-burnt piece of paper. ‘It was with my uncle’s papers. It’s his writing. Look, it says: