Перейти к выбору ответа 11.04.2022Если коэффициент трения покоя между бруском и вертикальной стеной 0,5, и прижимая брусок к стене горизонтальной силой 20 Н мы удерживаем его в покое, то чему равна масса бруска? Выбрать другой вопрос Смотреть ответ Перейти к выбору ответа Физика Ответ учителя по предмету Физика N=20H Коэфф.тр=0.5 Fтр=Fт=коэфф.тр*N=10H Fт=mg m=Fт/g=1кг
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X+(X+20)+X*2=90