Вопрос школьника по предмету Физика
Груз массой 25 кг равномерно поднимают с помошью неподвижного блока,прикладывая силу 270 Н.определить КПД блока.
Ответ учителя по предмету Физика
КПД=Апол/Азатр
Апол=mgh
Aзатр=Fh
КПД=mg/F
КПД=25×10/270=0.926=92,6%
Ответ 92,6%
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