Вопрос школьника по предмету Геометрия
В треугольнике ABC BM -медиана и BH -высота . Известно , что AC =17 и BC=BM. Найдите AH
Ответ учителя по предмету Геометрия
ВМ-медиана, точка М делит АС попалам,
АМ=МС=17÷2=8,5;
по условии ВС=ВМ; треугольник МВС равнобедренный, отсюда следует ВН высота является и медианой.
МН=НС=МС÷2=8,5÷2=4,25;
АН=АМ+МН=8,5+4,25=12,75.
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