Вопрос школьника по предмету Химия
вычислите массу кислорода, образовшегося при разложении 4 молей оксида ртути ||
Ответ учителя по предмету Химия
4mol Xmol
2HgO—>2Hg+O2
2mol 1mol
X=4*1/2=2 mol
m(O2)=n(O2)*M(O2) , M(O2)=32 g/mol
m(O2)=2*32=64 g
ответ 64 г
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