Вопрос школьника по предмету Геометрия
У прямокутному трикутнику ABC( кут c -90°) b — 8 см, а -40°, Знайди а, с та кут В
Ответ учителя по предмету Геометрия
Объяснение:
Δ ABC
<С=90°
b=АС=8см
<А=40°
а, с ,<В — ?
сумма внутренних углов треугольника равна 180°
<B=180° — <C -<A=180°-90°- 40°=50°
<B=50°
катет а=ВС=b/tg <B= 8/tg50°
гипотенуза
с=√ b²+a²=√8²+(8 /tg 50)²
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